6x^2=2.80(17-x)

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Solution for 6x^2=2.80(17-x) equation:



6x^2=2.80(17-x)
We move all terms to the left:
6x^2-(2.80(17-x))=0
We add all the numbers together, and all the variables
6x^2-(2.80(-1x+17))=0
We calculate terms in parentheses: -(2.80(-1x+17)), so:
2.80(-1x+17)
We multiply parentheses
-2.8x+47.6
Back to the equation:
-(-2.8x+47.6)
We get rid of parentheses
6x^2+2.8x-47.6=0
a = 6; b = 2.8; c = -47.6;
Δ = b2-4ac
Δ = 2.82-4·6·(-47.6)
Δ = 1150.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.8)-\sqrt{1150.24}}{2*6}=\frac{-2.8-\sqrt{1150.24}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.8)+\sqrt{1150.24}}{2*6}=\frac{-2.8+\sqrt{1150.24}}{12} $

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